Digital Electronics And Logic Design Set 1
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This set of Digital Electronics and Logic Design Multiple Choice Questions & Answers (MCQs) focuses on Digital Electronics And Logic Design Set 1
Q1 | The 2s compliment form (Use 6 bit word) of the number 1010 is
- 111100
- 110110
- 110111
- 1011
Q2 | AB+(A+B)’ is equivalent to
- a ex-nor b
- a ex or b
- (a+b)a
- (a+b)b
Q3 | The hexadecimal number equivalent to (1762.46)8 is
- 3f2.89
- 3f2.98
- 2f3.89
- 2f3.98
Q4 | A three input NOR gate gives logic high output only when
- one input is high
- one input is low
- two input are low
- all input are low
Q5 | The absorption law in Boolean algebra say that
- x + x = x
- x . y = x
- x + x . y = x
- none of the above
Q6 | Logic X-OR operation of (4ACO)H & (B53F)H results
- aacb
- 0
- abcd
- ffff
Q7 | What is decimal equivalent of (11011.1000)2 ?
- 22
- 22.2
- 20.2
- 27.5
Q8 | The negative numbers in the binary system can be represented by
- sign magnitude
- 2\s complement
- 1\s complement
- all of the above
Q9 | Negative numbers cannot be represented in
- signed magnitude form
- 1’s complement form
- 2’s complement form
- none of the above
Q10 | The answer of the operation (10111)2*(1110)2 in hex equivalence is
- 150
- 241
- 142
- 1.01e+08
Q11 | The Hexadecimal number equivalent of (4057.06)8 is
- 82f.027
- 82f.014
- 82f.937
- 83f.014
Q12 | The NAND gate output will be low if the two inputs are
- 0
- 1
- 10
- 11
Q13 | A binary digit is called a
- bit
- character
- number
- byte
Q14 | What is the binary equivalent of the decimal number 368
- 101110000
- 110110000
- 111010000
- 1.11e+08
Q15 | What is the binary equivalent of the Octal number 367
- 11110111
- 11100111
- 110001101
- 101110111
Q16 | What is the binary equivalent of the Hexadecimal number 368
- 1111101000
- 1101101000
- 1101111000
- 1.11e+09
Q17 | What is the binary equivalent of the decimal number 1011
- 1111110111
- 1111000111
- 1111110011
- 1.11e+09
Q18 | The gray code equivalent of (1011)2 is
- 1101
- 1010
- 1111
- 1110
Q19 | The decimal equivalent of hex number 1A53 is
- 6793
- 6739
- 6973
- 6379
Q20 | ( 734)8 =( )16
- c 1 d
- d c 1
- 1 c d
- 1 d c
Q21 | The simplification of the Boolean expression (A'BC')'+ (AB'C)' is
- 0
- 1
- a
- bc
Q22 | The hexadecimal number ‘A0’ has the decimal value equivalent to
- 80
- 256
- 100
- 160
Q23 | The Boolean expression A.B+ A.B+ A.B is equivalent to
- a + b
- a\.b
- (a + b)\
- a.b
Q24 | The 2’s complement of the number 1101101 is
- 101110
- 111110
- 110010
- 10011
Q25 | When simplified with Boolean Algebra (x + y)(x + z) simplifies to
- x
- x + x(y + z)
- x(1 + yz)
- x + yz