Digital Electronics And Logic Design Set 2
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This set of Digital Electronics and Logic Design Multiple Choice Questions & Answers (MCQs) focuses on Digital Electronics And Logic Design Set 2
Q1 | The code where all successive numbers differ from their preceding number by single bit is
- binary code.
- bcd.
- excess – 3.
- gray.
Q2 | -8 is equal to signed binary number
- 10001000
- oooo1000
- 10000000
- 11000000
Q3 | DeMorgan’s first theorem shows the equivalence of
- or gate and exclusive or gate.
- nor gate and bubbled and gate.
- nor gate and nand gate.
- nandgate and not gate
Q4 | When signed numbers are used in binary arithmetic, then which one of the following notations would have unique representation for zero.
- sign- magnitude.
- 1’s complement.
- 2’s complement.
- 9’s compleme nt.
Q5 | The decimal equivalent of Binary number 11010 is
- 26
- 36
- 16
- 23
Q6 | 1’s complement representation of decimal number of -17 by using 8 bit
- 1110 1110
- 1101 1101
- 1100 1100
- 0001 0001
Q7 | The excess 3 code of decimal number 26 is
- 0100 1001
- 1011001
- 1000 1001
- 1001101
Q8 | How many AND gates are required to realize Y = CD+EF+G
- 4
- 5
- 3
- 2
Q9 | The hexadecimal number for (95.5)10 is
- (5f.8) 16
- (9a.b) 16
- ( 2e.f) 16
- ( 5a.4) 16
Q10 | The octal equivalent of (247) 10 is
- ( 252) 8
- (350) 8
- ( 367) 8
- ( 400) 8
Q11 | The number 140 in octal is equivalent to
- (96)10 .
- ( 86) 10
- (90) 10 .
- none of these.
Q12 | The NOR gate output will be low if the two inputs are
- 11
- 1
- 10
- all
Q13 | Convert decimal 153 to octal. Equivalent in octal will be
- (231)8
- ( 331) 8
- ( 431) 8 .
- none of these.
Q14 | The decimal equivalent of ( 1100)2 is
- 12
- 16
- 18
- 20
Q15 | The binary equivalent of (FA)16 is
- 1010 1111
- 1111 1010
- 10110011
- none of these
Q16 | How many two-input AND and OR gates are required to realize Y=CD+EF+G
- 22
- 23
- 33
- none of these
Q17 | The excess-3 code of decimal 7 is represented by
- 1100
- 1001
- 1011
- 1010
Q18 | When an input signal A=11001 is applied to a NOT gate serially, its output signal is
- 111
- 110
- 10101
- 11001
Q19 | The result of adding hexadecimal number A6 to 3A is
- dd
- e0
- f0
- ef
Q20 | A universal logic gate is one, which can be used to generate any logic function. Which of the following is a universal logic gate?
- or
- and
- xor
- nand
Q21 | Karnaugh map is used for the purpose of
- reducing the electronic circuits used.
- to map the given boolean logic function.
- to minimize the terms in a boolean expression.
- to maximize the terms of a given a boolean expression.
Q22 | The 2’s complement of the number 1101110 is
- 10001
- 10001
- 10010
- none
Q23 | The decimal equivalent of Binary number 10101 is
- 21
- 31
- 26
- 28
Q24 | How many two input AND gates and two input OR gates are required to realize Y = BD+CE+AB
- 11
- 42
- 32
- 23
Q25 | Which of following are known as universal gates
- nand & nor
- and & or.
- xor & or.
- none.