Fluid Mechanics And Machinery Set 8 MCQs

Q1 | The flow rate of steam is controlled by regulating the

steam

pressure

temperature

speed

Q2 | What is primary objective of steam turbine governing?

maintain constant speed

maintain constant pressure

maintain constant temperature

maintain constant expansion

Q3 | governing?

controls speed

controls flow rate

controls volume

controls discharge

Q4 | Which among the following control the flow rate?

valve

pump

head

tank pipe

Q5 | The advantage of nozzle governing is that no regulating pressure is applied.

true

false

Q6 | During the steam turbine governing, what remains a constant?

speed of rotation

flow rate

pump head

volume of fluid

Q7 | When do we apply by pass governing?

when turbine is overloaded

when unit speed decreases

when unit power increases

when unit pressure decreases

Q8 | When bypass valve is opened to

increase pressure

increase unit speed

increase unit power

increase the amount of fresh steam

Q9 | What is the unit of steam rate?

kg

kg/m

kg/kwh

n/m

Q10 | turbine

decreases

increases

remains same

independent

Q11 | Combination governing involves usage of two or more governing.

true

false

Q12 | increases beyond 110 percent, we use

throttle governing

steam governing

nozzle governing

emergency governing

Q13 | Which one of the following is the unit of mass density?

kg = m3

kg = m2

kg = m

kg = ms

Q14 | The specific gravity of a liquid has

the same unit as that of mass density

the same unit as that of weight density

the same unit as that of specific volume

no unit

Q15 | The specific volume of a liquid is the reciprocal of

weight density

mass density

specific weight

specific volume

Q16 | Which one of the following is the unit of specific weight?

n = m3

n = m2

n = m

n = ms

Q17 | Which one of the following is the dimension of mass density?

[m1 l-3 t0].

[m1 l3 t0].

[m0 l-3 t0].

[m0 l3 t0].

Q18 | ] = [ML-3].

[m1 l-3 t0].

[m1 l0 t0].

[m0 l-3 t0].

[m0 l0 t0].

Q19 | ]/[M] = [M-1L3].

[ml-3 t -2].

[ml3 t-2].

[ml-2 t-2].

[ml2 t-2].

Q20 | and v2?

v1 > v2

v1 < v2

v1 = v2

cannot be determined due to insufficient information.

Q21 | A beaker is filled with a liquid up to the mark of one litre and weighed. The weight of the liquid is found to be 6.5 N. The specific weight of the liquid will be

6:5 kn = m3

6:6 kn = m3

6:7 kn = m3

6:8 kn = m3

Q22 | A beaker is filled with a liquid up to the mark of one litre and weighed. The weight of the liquid is found to be 6.5 N. The specific gravity of the liquid will be

0.65

0.66

0.67

0.68

Q23 | A beaker is filled with a liquid up to the mark of one litre and weighed. The weight of the liquid is found to be 6.5 N. The specific volume of the liquid will be

1 l =kg

1:5 l =kg

2 l =kg

2:5 l =kg

Q24 | The physical principle behind the continuity equation is

mass conservation

zeroth law of thermodynamics

first law of thermodynamics

energy conservation

Q25 | To convert the non-conservative integral equation of mass conservation into the conservative integral form, which of these theorems is used?

stokes theorem

kelvin-stokes theorem

gauss-siedel theorem

gauss divergence theorem