On This Page
This set of Digital Logic Circuits DLC Multiple Choice Questions & Answers (MCQs) focuses on Digital Logic Circuits Set 12
Q1 | A variable on its own or in its complemented form is known as a
- product term
- literal
- sum term
- word
Q2 | Canonical form is a unique way of representing
- sop
- minterm
- boolean expressions
- pos
Q3 | There are Minterms for 3 variables (a, b, c).
- 0
- 2
- 8
- 1
Q4 | Why is a demultiplexer called a data distributor?
- the input will be distributed to one of the outputs
- one of the inputs will be selected for the output
- the output will be distributed to one of the inputs
- single input gives single output
Q5 | Most demultiplexers facilitate which type of conversion?
- decimal-to-hexadecimal
- single input, multiple outputs
- ac to dc
- odd parity to even parity
Q6 | In 1-to-4 demultiplexer, how many select lines are required?
- 2
- 3
- 4
- 5
Q7 | In a multiplexer the output depends on its
- data inputs
- select inputs
- select outputs
- enable pin
Q8 | In 1-to-4 multiplexer, if C1 = 1 & C2 = 1, then the output will be
- y0
- y1
- y2
- y3
Q9 | How many select lines are required for a 1-to-8 demultiplexer?
- 2
- 3
- 4
- 5
Q10 | How many AND gates are required for a 1-to-8 multiplexer?
- 2
- 6
- 8
- 5
Q11 | Which IC is used for the implementation of 1-to-16 DEMUX?
- ic 74154
- ic 74155
- ic 74139
- ic 74138
Q12 | The word demultiplex means
- one into many
- many into one
- distributor
- one into many as well as distributor
Q13 | Why is a demultiplexer called a data distributor?
- the input will be distributed to one of the outputs
- one of the inputs will be selected for the output
- the output will be distributed to one of the inputs
- single input to single output
Q14 | In a multiplexer the output depends on its
- data inputs
- select inputs
- select outputs
- enable pin
Q15 | In 1-to-4 multiplexer, if C1 = 0 & C2 = 1, then the output will be
- y0
- y1
- y2
- y3
Q16 | In 1-to-4 multiplexer, if C1 = 1 & C2 = 1, then the output will be
- y0
- y1
- y2
- y3
Q17 | What is the addition of the binary numbers 11011011010 and 010100101?
- 0111001000
- 1100110110
- 11101111111
- 10011010011
Q18 | Perform binary addition: 101101 + 011011 = ?
- 011010
- 1010100
- 101110
- 1001000
Q19 | Binary subtraction of 100101 – 011110 is
- 000111
- 111000
- 010101
- 101010
Q20 | Perform multiplication of the binary numbers: 01001 × 01011 = ?
- 001100011
- 110011100
- 010100110
- 101010111
Q21 | 100101 × 0110 = ?
- 1011001111
- 0100110011
- 101111110
- 0110100101
Q22 | On multiplication of (10.10) and (01.01), we get
- 101.0010
- 0010.101
- 011.0010
- 110.0011
Q23 | Divide the binary numbers: 111101 ÷ 1001 and find the remainder
- 0010
- 1010
- 1100
- 0011
Q24 | Divide the binary number (011010000) by (0101) and find the quotient
- 100011
- 101001
- 110010
- 010001
Q25 | Binary subtraction of 101101 – 001011 = ?
- 100010
- 010110
- 110101
- 101100