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This set of Structural Mechanics Multiple Choice Questions & Answers (MCQs) focuses on Structural Mechanics Set 5

Q1 | The moment of inertia of a body is always minimum with respect to its

- Base
- Centroidal axis
- Vertical axis
- Horizontal axis

Q2 | Moment of inertia is the

- Second moment of area
- Second moment of mass
- Second moment of force
- All of these

Q3 | In a simply supported beam carrying a uniformly distributed load W/m over the left half span, the point of contra flexure will occur in

- Left half span of the beam
- Right half span of the beam.
- Quarter points of the beam
- Does not exist

Q4 | A sudden increase or decrease in shear force diagram between any twopoints indicates that there is

- No loading between the two points
- Point loads between the two points
- U.D.L. between the two points
- None of these

Q5 | When the bending moment is parabolic curve between two points, it indicates that there is

- No loading between the two points
- Point loads between the two points
- U.D.L. between the two points
- Uniformly varying load between the two points

Q6 | In Fig.(a), max B.M. will be

- 40 kN-m
- 50 kN-m
- 60 kN-m
- 80 kN-m

Q7 | In Fig. (a), slope of S.F.D. between B and C will be

- Zero
- 10 kN
- 15 kN
- 20 kN

Q8 | What is the bending moment at end supports of a simply supported beam?

- Maximum
- Minimum
- Zero
- Uniform

Q9 | What is the maximum shear force, when a cantilever beam is loaded withudl throughout?

- w×l
- w
- w/l
- w+l

Q10 | Sagging, the bending moment occurs at the of the beam.

- At supports
- Mid span
- Point of contraflexure
- Point of emergence

Q11 | What will be the variation in BMD for the diagram? [Assume l = 2m].

- Rectangular
- Trapezoidal
- Triangular
- Square

Q12 | What is the maximum bending moment for simply supported beam carrying a point load “W” kN at its centre?

- W kNm
- W/m kNm
- W×l kNm
- W×l/4 kNm

Q13 | How do point loads and udl be represented in SFD?

- Simple lines and curved lines
- Curved lines and inclined lines
- Simple lines and inclined lines
- Can’t represent any more

Q14 | curve is formed due to bending of overhanging beams.

- Elastic
- Plastic
- Flexural
- Axial

Q15 | The relation between slope and maximum bending moment is

- Directly proportion
- Inversely proportion
- Relative proportion
- Mutual incidence

Q16 | What is the SF at support B?

- 5 kN
- 3 kN
- 2 kN
- 0 kN

Q17 | Where do the maximum BM occurs for the below diagram.

- -54 kNm
- -92 kNm
- -105 kNm
- – 65 kNm

Q18 | Shear force is unbalanced to the left or right of the section.

- Horizontal force
- Vertical force
- Inclined force
- Conditional force

Q19 | SI units of shear force is

- kN/m
- kN-m
- kN
- m/N

Q20 | Determine the moment at fixed end.

- 40 kNm
- 50 kNm
- 60 kNm
- 80 kNm

Q21 | Shear force diagram is representation of shear force plotted as ordinate.

- Scalar
- Aerial
- Graphical
- Statically

Q22 | Hogging is

- Negative bending moment
- Positive shear force
- Positive bending moment
- Negative shear force

Q23 | At the point of contraflexure, the value of bending moment is

- Zero
- Maximum
- Can’t be determined
- Minimum

Q24 | Positive/negative bending moments occur where shear force changes its sign.

- Minimum
- Zero
- Maximum
- Remains same

Q25 | Shear force of following diagram

- Rectangle
- Square
- Circle
- Trapezoidal