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This set of Design of Steel Structures Multiple Choice Questions & Answers (MCQs) focuses on Design Of Steel Structures Set 18
Q1 | IS : 800 - 1971 recommends that in a splice plate the number of rivets carrying calculated shear stress through a packing greater than 6 mm thick, is to be increased by 2.5% for every
- 1.00 mm thickness of packing
- 1.50 mm thickness of packing
- 2.0 mm thickness of packing
- 2.50 mm thickness of packing
Q2 | To the calculated area of cover plates of a built-up beam, an allowance for rivet holes to be added, is
- 10 %
- 13 %
- 15 %
- 18 %
Q3 | If the moment of inertia of a section about its axis is and its effective sectional area is, its radius of gyration r about the axis, is
- r = I/A
- r I/A)
- r = (I/A)
- r A/I)
Q4 | A structural member subjected to compressive stress in a direction parallel to its longitudinal axis, is generally known as
- Column
- Stanchion
- Post
- All the above
Q5 | The equivalent axial tensile load Pe, which produces an average axial tensile stress in the section equivalent to the combined stress due to axial tension P and bending M, at the extreme fibre of the section, is given by (where Z is the section modulus of the section).
- Pe = P + MA/Z
- Pe = P - MA/Z
- Pe = P - Z/MA
- Pe = P + Z/MA
Q6 | For the steel member exposed to weather and accessible for repainting, the thickness of steel should not be less than (accepting the webs of Indian Standard rolled steel joists and channels).
- 4 mm
- 6 mm
- 8 mm
- 10 mm
Q7 | The distance measured along one rivet line from the centre of a rivet to the centre of adjoining rivet on an adjacent parallel rivet line, is called
- Pitch of rivet
- Gauge distance of rivet
- Staggered pitch
- All the above
Q8 | The effective length of a simply supported beam with ends restrained against torsion, and also the ends of compression flange partially restrained against lateral bending, is given by
- L = span
- L = 0.85 span
- L = 0.75 span
- L = 0.7 span
Q9 | Strengths of a rivet in single shearing, in bearing and in tearing are 3425 kg, 4575 kg and 5025 kg respectively. If the load in the member is 35 tonnes, the number of rivets required, is
- 10
- 11
- 12
- 13
Q10 | A simply supported beam carrying a central load, will be safe in deflection if the ratio of its span to depth, is
- < 19
- < 24
- > 19
- > 24
Q11 | When a load is transferred through one surface to another surface in contact, thestress is known as
- Tensile stress
- Compressive stress
- Shearing stress
- None of these
Q12 | A 20 mm dia steel bar which is subjected to an axial tension of 2300 kg/cm2 produces a strain of cm. If Young's modulus of steel is 2.1 × 106kg/cm2, the bar is
- In the elastic range
- In the plastic range
- At yield point
- None of these
Q13 | The maximum axial load which is just sufficient to keep a column in a smalldeflected shape, is called
- Crippling load
- Buckling load
- Critical load
- All the above
Q14 | Spans of continuous fillers are considered approximately equal if the longest span does not exceed the shortest span by more than
- 5 %
- 10 %
- 15 %
- 20 %
Q15 | The ratio of the span L of the filler joists to the depth d from the underside of the joist to the top of the structural concrete, should not exceed
- 60
- 45
- 35
- 25
Q16 | The allowable stress in axial tension is generally kept less if thickness of themember is more than
- 10 mm
- 12 mm
- 15 mm
- 20 mm
Q17 | The maximum permissible slenderness ratio of compression membercarrying dead and superimposed load, is
- 180
- 200
- 250
- 350
Q18 | Tacking rivets in compression plates not exposed to the weather, have a pitch not exceeding 300 mm or
- 16 times the thickness of outside plate
- 24 times the thickness of outside plate
- 32 times the thickness of outside plate
- 36 times the thickness of outside plate
Q19 | A single angle in tension is connected by one leg only. If the areas of connecting and outstanding legs are respectively a and b, net effective area of the angle, is
- a - [b/{1 + 0.35 (b/a)}]
- a + [b/{1 + 0.35 (b/a)}]
- a - [b/{1 + 0.2 (b/a)}]
- a + [b/{1 + 0.2 (b/a)}]
Q20 | If L is the overall length of a combined footing having A as its area, d being the distance between the centre of gravity of the base and centre of the base, the larger width b is
- (A/L) + (3Ad/L²)
- (A/L) + (6Ad/L²)
- (A/L) - (6Ad/L²)
- (A/L) - (3Ad/L²)