Digital Electronics Set 4

Electrical Engineering,

Bachelor of Science in Computer Science FY (BSc CS),

Bachelor of Computer Applications (BCA),

Bachelor of Science in Computer Science (BSc CS)

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This set of Digital Electronics Multiple Choice Questions & Answers (MCQs) focuses on Digital Electronics Set 4

Q1 | Convert 59.7210 to BCD.
  • 111011
  • 01011001.01110010
  • 1110.11
  • 0101100101110010
Answer: 01011001.01110010
Q2 | Convert 8B3F16 to binary.
  • 35647
  • 011010
  • 1011001111100011
  • 1000101100111111
Answer: 1000101100111111
Q3 | Which is typically the longest: bit, byte, nibble, word?
  • bit
  • byte
  • nibble
  • word
Answer: word
Q4 | Assign the proper odd parity bit to the code 111001.
  • 1111011
  • 1111001
  • 0111111
  • 0011111
Answer: 1111001
Q5 | Convert decimal 64 to binary.
  • 01010010
  • 01000000
  • 00110110
  • 01001000
Answer: 01000000
Q6 | Convert hexadecimal value C1 to binary.
  • 11000001
  • 1000111
  • 111000100
  • 111000001
Answer: 11000001
Q7 | The given hexadecimal number (1E.53)16 is equivalent to                          
  • (35.684)8
  • (36.246)8
  • (34.340)8
  • (35.599)8
Answer: (36.246)8
Q8 | The octal number (651.124)8 is equivalent to              
  • 16
  • (1b0.10)16
  • (1a8.a3)16
  • (1b0.b0)16
Answer: 16
Q9 | The octal equivalent of the decimal number (417)10 is            
  • (641)8
  • (619)8
  • (640)8
  • (598)8
Answer: (641)8
Q10 | Convert the hexadecimal number (1E2)16 to decimal:
  • 480
  • 483
  • 482
  • 484
Answer: 482
Q11 | (170)10 is equivalent to
  • (fd)16
  • (df)16
  • (aa)16
  • (af)16
Answer: (aa)16
Q12 | Convert the binary number (01011.1011)2 into decimal:
  • (11.6875)10
  • (11.5874)10
  • (10.9876)10
  • (10.7893)10
Answer: (11.6875)10
Q13 | 1011)2 = (11.6875)10
  • (111101)2
  • (010100)2
  • (111100)2
  • (101010)2
Answer: (010100)2
Q14 | On addition of +38 and -20 using 2’s complement, we get                          
  • 11110001
  • 100001110
  • 010010
  • 110101011
Answer: 010010
Q15 | On addition of -46 and +28 using 2’s complement, we get                          
  • 00101110
  • 0101110
  • 00101111
  • 1001111
Answer: 0101110
Q16 | On subtracting +28 from +29 using 2’s complement, we get                          
  • 11111010
  • 111111001
  • 100001
  • 1
Answer: 1
Q17 | The decimal number 10 is represented in its BCD form as                      
  • 10100000
  • 01010111
  • 00010000
  • 00101011
Answer: 00010000
Q18 | When numbers, letters or words are represented by a special group of symbols, this process is called                      
  • decoding
  • encoding
  • digitizing
  • inverting
Answer: encoding
Q19 | Carry out BCD subtraction for (68) – (61) using 10’s complement method.
  • 00000111
  • 01110000
  • 100000111
  • 011111000
Answer: 00000111
Q20 | How many bits would be required to encode decimal numbers 0 to 9999 in straight binary codes?
  • 12
  • 14
  • 16
  • 18
Answer: 14
Q21 | The decimal equivalent of the excess-3 number 110010100011.01110101 is
  • 970.42
  • 1253.75
  • 861.75
  • 1132.87
Answer: 970.42
Q22 | In boolean algebra, the OR operation is performed by which properties?
  • associative properties
  • commutative properties
  • distributive properties
  • all of the mentioned
Answer: all of the mentioned
Q23 | The expression for Absorption law is given by                    
  • a + ab = a
  • a + ab = b
  • ab + aa’ = a
  • a + b = b + a
Answer: a + ab = a
Q24 | According to boolean law: A + 1 = ?
  • 1
  • a
  • a’
Answer: 1
Q25 | The involution of A is equal to                    
  • a
  • a’
  • 1
Answer: a
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