You are doing a genetics experiment with the fruit fly. In the "P" generation, you cross two true-breeding flies. The female parent is brown and wingless and the male parent is black with normal wings. All of the flies in the F1 generation are brown and h
BBnn female
bbNN male
You have BBnn female crossed with bbNN male. Brown (B) is dominant to black (b) Winged (N) is dominant to wingless (n)
What is the genotype of the F1 generation
100% BbNn
You have BbNn female crossed with bbnn male. Brown (B) is dominant to black (b) Winged (N) is dominant to wingless (n)
You have 1600 offspring and you get 0 BbNn, 800 Bbnn, 800 bbNn, and 0 bbnn. What can you assume about these genes?
They must be linked and no recombination occurred.
You have BbNn female crossed with bbnn male. Brown (B) is dominant to black (b) Winged (N) is dominant to wingless (n)
You have 1600 offspring. You have determined that the genes are linked. You end up with 85 brown winged, 728 black winged, 712 brown win
The recombinants are the 75 black wingless and the 85 brown winged. 75+85 = 160
160/1600=0.10
0.10 x 100= 10%
What is the formula for Recombination Frequency?
# of recombinants/ total (100)
You have determined that wing size and color are 10 centimorgans apart. You discover that wing size and antenna length has a recombination frequency of 5%. What would a gene map of these 3 linked genes look like?
It could be antenna wing color or color antenna wing (remember they can be backwards too)
You cross a true-breeding yellow-bodied, smooth-winged female with a true-breeding red-bodied, crinkle winged male. What will be the phenotype(s) of the F1 progeny? (The red body phenotype is dominant to the yellow body phenotype and smooth wings are domi
RRaa X rrAA = RrAa
100% will have red bodies and smooth wings.
(The red body phenotype is dominant to the yellow body phenotype and smooth wings are dominant to crinkled
wings). What is the predicted ratio of phenotypes from crossing RrAa X RrAa?
9 : 3 : 3 : 1 red smooth: red crinkled: yellow smooth: yellow crinkled
(The red body phenotype is dominant to the yellow body phenotype and smooth wings are dominant to crinkled
wings) You cross BbAa X bbaa. You get the following:
396 red crinkled
404 yellow smooth
102 red smooth
98 yellow smooth
What is the distance between
(102+98)/(396+102+98+404) *100= 20 cM