conditions of z-procedure on proportions
1. random
2. 10% Rule
3. Large Enough: np>10 ; n(1-p)>10
*Summary Statement
conditions of 2 sample z-procedure on proportions
1. random assignment/independence
2. Large Enough: n1p1>10 ; n1(1-p1)>10 AND n2p2>10 ; n2(1-p2)>10
conditions of t-procedure on means
1. random sample
2. approx. normal
*given
*n>30
*graph (normal probability)
3. ? is unknown
conditions of 2 sample t-procedure on means
1. samples independently selected
2. each sample is random
3. Large Enough: n1>30 ; n2>30
conditions of match pairs t-procedure
1. samples are paired
2. Large Enough: nd>30
3. random samples
confidence interval for z-procedure on proportions
p�z*?p(1-P)/n
confidence interval for 2 sample z-procedure on proportions
p1-p2�z*(?(p1(1-P)/n2)+(p2(1-p2)/n2))
confidence interval for t-procedure on means
x?�t*(s/?n)
confidence interval for 2 sample t-procedure on means
(x?1-x?2)�t*?(s1�/n1)+(s2�/n2)
confidence interval for match pairs t-procedure
x?d�t*(sd/?n)
z-score for z-procedure on proportions
Z=(p?-p)/(?p(1-p)/n)
z-score for 2 sample z-procedure on proportions
Z=(p?1-p?2)/(?((p?1(1-p?1))/n1)+((p?2(1-p?2))/n2)))
t-score for t-procedure on means
t=(x?-?)/(s/?n)
t-score for 2 sample t-procedure on means
t=(x?1-x?2)/?((s1�/n1)+(s2�/n2))
t-score for match pairs t-procedure
t=(x?d-?d(*0))/(sd/?n)
hypothesis test z-procedure on proportions
p=,<,>_____
hypothesis test 2 sample z-procedure on proportions
p1=,<,>p2
hypothesis test t-procedure on means
?=,<,>_____
hypothesis test 2 sample t-procedure on means
?1=,<,>?2
hypothesis test match pairs t-procedure
?d=,<,>0