Let u=<3,6>, v=<-8,2> and w=<2,-1>find:a)3v+2w-1/3u
<-8*3,2*3>+<2*2,-1*2>-<(1/3)*3,(1/3)*6>=<-24+4-1, 6-2-2>=<-21,2>
Find the Vector AB if AB has for initial point <-8,2> and for end point<3,6>
AB=<3+8, 6-2>=<11,4>
A complex number z is given in exponential form as:z=12ei2(pi)/3
z=12(cos2(pi)/3+isin2(pi)/3)
convert this: z=12(cos2(pi)/3+isin2(pi)/3) to the rectangular form
=12(-1/2+i sq. root of 3/2)=z=-6+i6 sq.root of 3
let z=5 +12i=reithetaConvert to the exponential form
r2=52+122=25+144=169r=sq root of 169=13tan theta=b/a=12/5theta=tan-1(12/5)= 67.4z=13ei67.4
convert z to polar formz=13ei67.4
z=13(cos67.4+isin67.4)
find z3
z=4ei2(pi)/3z3=43ei3(2(pi)/3) =64ei2(pi) =64(cos2(pi)+isin2(pi)) =64(1+i0)=64z3 =64